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S1mb4 D4 L10n wrote:Is there any simple way to do this? If 2^n = x, n is the amount of bits it takes to represent one digit in base x. But lets say we have an even number that is not a power of 2 as a base, how would we group that. Base 6? 2^2 + 2^1 = 6, so would we add 2 bits to 1 other bit to produce a digit in base 6? My mind is spinning. I need to test this.




























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